6[3-(4+4x)]-4x=-8+2(1-14x)

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Solution for 6[3-(4+4x)]-4x=-8+2(1-14x) equation:


Simplifying
6[3 + -1(4 + 4x)] + -4x = -8 + 2(1 + -14x)
6[3 + (4 * -1 + 4x * -1)] + -4x = -8 + 2(1 + -14x)
6[3 + (-4 + -4x)] + -4x = -8 + 2(1 + -14x)

Combine like terms: 3 + -4 = -1
6[-1 + -4x] + -4x = -8 + 2(1 + -14x)
[-1 * 6 + -4x * 6] + -4x = -8 + 2(1 + -14x)
[-6 + -24x] + -4x = -8 + 2(1 + -14x)

Combine like terms: -24x + -4x = -28x
-6 + -28x = -8 + 2(1 + -14x)
-6 + -28x = -8 + (1 * 2 + -14x * 2)
-6 + -28x = -8 + (2 + -28x)

Combine like terms: -8 + 2 = -6
-6 + -28x = -6 + -28x

Add '6' to each side of the equation.
-6 + 6 + -28x = -6 + 6 + -28x

Combine like terms: -6 + 6 = 0
0 + -28x = -6 + 6 + -28x
-28x = -6 + 6 + -28x

Combine like terms: -6 + 6 = 0
-28x = 0 + -28x
-28x = -28x

Add '28x' to each side of the equation.
-28x + 28x = -28x + 28x

Combine like terms: -28x + 28x = 0
0 = -28x + 28x

Combine like terms: -28x + 28x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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